Y=-0.1x^2+1.6

Solution for Y=-0.1x^2+1.6 equation:

=-0.1Y^2+1.6

We move all terms to the left:

-(-0.1Y^2+1.6)=0

We get rid of parentheses

0.1Y^2-1.6=0

a = 0.1; b = 0; c = -1.6;
Δ = b2-4ac
Δ = 02-4·0.1·(-1.6)
Δ = 0.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.64}}{2*0.1}=\frac{0-\sqrt{0.64}}{0.2}
=-\frac{\sqrt{}}{0.2}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.64}}{2*0.1}=\frac{0+\sqrt{0.64}}{0.2}
=\frac{\sqrt{}}{0.2}
$